有 以下程序
void f(int b[])
{ int i;
for(i=2;i<6;i++) b[i]*=2;
}
main( )
{ int a[10]={1,2,3,4,5,6,7,8,9,10},i;
f(a);
for(i=0;i<10;i++) printf("%d",a[i]);
}
程序运行后的输出结果是
A)1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 ,
B)1 , 2 , 6 , 8 , 10 , 12 , 7 , 8 , 9,10
C)1 , 2 , 3 , 4 , 10 , 12 , 14 , 16 , 9 , 10 ,
D)1 , 2 , 6 , 8 , 10 , 12 , 14 , 16 , 9 , 10 ,
●设有关键码序列(16,9,4,25,15,2,13,18,17,5,8,24),要按关键码值递增的次序排序,采用直接选择排序法,一趟扫描后的结果为 (5) 。
(5) A.(2,9,4,25,15,16,13,18,17,5,8,24)
B.(15,2,4,18,16,5,8,24,17,9,13,25)
C.(9,4,16,15,2,13,18,17,5,8,24,25)
D.(9,16,4,25,2,15,13,18,5,17,8,24)
计算:
(1)(-8)+(-9); (2)(-17)+21;
(3)(-12)+25; (4)45+(-23); (5)(-45)+23 (6)(-29)+(-31);
(7)(-39)+(-45) (8)(-28)+37; (9)(-13)+0.
(1)-17;(2)4;(3)13;
(4)22;(5)-22;(6)-60;
(7)-84;(8)9;(9)-13.
(1)0×(-2012); (2)(-8)×1.25 ;
(3)7/10×(-3/14)
(4)(-3/16)×(-8/9)
(5)7.5×(-8.2)×0×(-19.1)
(6)(-14/3)×5/7
(7)(-0.12)×1/12×(-100)
(8)7×(-1+3/14)
(1)0 (2)-10 (3) -3/20 (4)1/6
(5) 0 (6)-10/3 (7) 1 (8)-11/2
计算:
(1)36×(1/2-1/3)2
(2)12.7÷(-8/19) ×0
(3)4×(-3)2+6
(4)(-3/4)×(-8+2/3-1/3)
(5)(-2)3-13÷(-1/2)
(6)0-23÷(-4)3-1/8
(7)(-2)3×0.5-(-1.6)2÷(-2)2
(8)(-3/2)×[(-2/3)2-2]
(9)[(-3)2-(-5)2] ÷(-2)
(10)16÷(-2)3-(-1/8) ×(-4)
(1)1; (2)0; (3)42; (4)5.75; (5)18; (6)0; (7)-4.64; (8)4/3; (9) -8; (10)-2/3
5-15?-16 ?05-15?-16 ? 1 ? ? QQ?915446173 ? QQ?915446173? ? ? ? ? 2016 ? V6.02016 ? V6.0 ? -?-? ? ? 05-15? 05-15? ? ? ? QQ?915446173 ? 2016 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?05-15?-16 ?05-15?-16 ? 2 ? ? QQ?915446173 ? QQ?915446173? ? ? ? . 4 ? . 5 ? . 8 1? . 8 2? . 9 3?ERP? . 10 4?CRM? . 12 5? . 13 6? BI . 17 7? . 18 ? . 23 1? . 23 2? . 26 3? . 30 4? . 35 5? . 37 6? .
计算:
(1)(-8)-(-1) (2)45+(-30)
(3)-1.5-(-11.5) (4)-1/4-(-1/2)
(5)15-[1-(-20-4)] (6)-40-28-(-19)+(-24)
(7)22.54+(-4.4)+(-12.54)+4.4
(8) (2/3-1/2)-(1/3-5/6)
(9)2.4-(-3/5)+(-3.1)+4/5 (10)(-6/13)+(-7/13)-(-2)
(11)3/4-(-11/6)+(-7/3)
(12)11+(-22)-3×(-11)
(13)(-0.1)÷1/2×(-100)
(14)(-3/4)×(-2/3 - 1/3) ×0
(15)(-2)3-32
(16)23÷[(-2)3-(-4)]
(17)(3/4-7/8)÷(-7/8)
(18)(-60)×(3/4+5/6)
(1)(-8)-(-1)=-7
(2)45+(-30)=15
(3)-1.5-(-11.5)=10
(4)-1/4-(-1/2)=1/4
(5)15-[1-(-20-4)]=-10 (6)-40-28-(-19)+(-24)=-73
(7)22.54+(-4.4)+(-12.54)+4.4=10
(8) (2/3-1/2)-(1/3-5/6)=-1
(9)2.4-(-3/5)+(-3.1)+4/5=0.7 (10)(-6/13)+(-7/13)-(-2)=1
(11)3/4-(-11/6)+(-7/3)=1/4
(12)11+(-22)-3×(-11)=22
(13)(-0.1) ÷1/2×(-100)=20
(14)(-3/4) ×(-2/3 - 1/3) ×0=0
(15)(-2)3-32=-17
(16)23÷[(-2)3-(-4)]=-23/4
(17)(3/4-7/8) ÷(-7/8)=1/7
(18)(-60) ×(3/4+5/6)=-95
观察下面的每列数,按某种规律在横线上填上适当的数,并说明你的理由。
(1)-23,-18,-13,______,______;
(2)2/8,-3/16,4/32,-5/64,_____,_______;
(3 ) 2,- 4 ,8,-16,______,_______;
(4)-2,-4, 0,-2, 2,______,_______。
(1)-8,-3;
(2)6/128,-7/256;
(3 )32,-64;
(4)0,4
采用初始增量为4的希尔排序法对没有关键码序列{15,10,4,26,14,2,13,19,17,5,9, 23},按照关键码值递增的次序排序,一趟扫描后的结果为
A.{14,2,4,19,15,5,9,23,17,10,13,26}
B.{2,9,4,26,14,15,13,19,17,5,9,23}
C.{10,4,15,14,2,13,19,16,5,9,23,26}
D.{10,15,4,2,14,13,19,16,5,9,23,26}
采用初始增量为4的希尔排序法对没有关键码序列{15,10,4,26.14,2,13,19,17,5,9, 23},按照关键码值递增的次序排序,一趟扫描后的结果为
A.{14,2,4,19,15,5,9,23,17,10,13,26}
B.{2,9,4,26,14,15,13,19,17.5,9,23}
C.{10,4,15,14,2,13,19,16,5,9,23.26}
D.{10,15,4,2,14,13,19,16,5,9,23,26}
1.publicclassTest{2.publicstaticStringoutput=””;3.4.publicstaticvoidfoo(inti){5.try{6.if(i==1){7.thrownewException();8.}9.output+=“1”;10.}11.catch(Exceptione){12.output+=“2”;13.return;14.}15.finally{16.output+=“3”;17.}18.output+=“4”;19.}20.21.publicstaticvoidmain(Stringargs[]){22.foo(0);23.foo(1);24.25.}26.}Whatisthevalueofthevariableoutputatline23?()